Parabolas
MAT1501 - Fundamental Mathematics · MODULE 3: GRAPHS
Parabolas
A parabola is the graph of a quadratic function. Quadratic functions can model various real-world scenarios, such as projectile motion. Understanding parabolas is important for solving problems in mathematics, physics, and engineering.
Key idea: After studying this topic, you should be able to:
- Identify the characteristics of parabolas defined by the equation y = ax² + bx + c.
- Sketch parabolas using their vertex and intercepts.
- Find the equation of a parabola given certain points.
- Use parabolas to solve quadratic inequalities.
Understanding Parabolas
A parabola is defined by a quadratic function of the form:
f(x) = ax² + bx + c
where a, b, and c are constants and a ≠ 0. The graph of this function is a curve that opens either upwards or downwards depending on the sign of a:
- If a > 0, the parabola opens upwards.
- If a < 0, the parabola opens downwards.
Characteristics of Parabolas
Vertex
The vertex of a parabola is the highest or lowest point on the graph, depending on whether it opens upwards or downwards. The vertex can be found using the formula:
Vertex: (h, k) where h = -b/(2a) and k = f(h).
Axis of Symmetry
The axis of symmetry is a vertical line that passes through the vertex. Its equation is:
x = h.
Intercepts
The y-intercept can be found by substituting x = 0 into the equation:
y-intercept: (0, c).
The x-intercepts can be found by solving the equation:
ax² + bx + c = 0.
Example: Finding the Vertex and Axis of Symmetry
Consider the quadratic function:
f(x) = 2x² - 4x + 1.
To find the vertex:
- Calculate h: h = -(-4)/(2 * 2) = 1.
- Calculate k: k = f(1) = 2(1)² - 4(1) + 1 = -1.
The vertex is (1, -1). The axis of symmetry is x = 1.
Sketching Parabolas
To sketch a parabola, follow these steps:
- Identify the vertex and plot it on the graph.
- Find the y-intercept and plot it.
- Find the x-intercepts, if they exist, and plot them.
- Draw the axis of symmetry.
- Sketch the curve, ensuring it is symmetric about the axis of symmetry.
Example: Sketching a Parabola
Using the function from the previous example:
f(x) = 2x² - 4x + 1.
1. Vertex: (1, -1).
2. y-intercept: (0, 1).
3. x-intercepts: Solve 2x² - 4x + 1 = 0 using the quadratic formula:
x = [4 ± √((-4)² - 4 * 2 * 1)]/(2 * 2) = [4 ± √(16 - 8)]/4 = [4 ± √8]/4 = [4 ± 2√2]/4 = 1 ± √2/2.
4. The x-intercepts are approximately (2.414, 0) and (-0.414, 0).
Now plot these points and sketch the parabola.
Discriminant and Roots
The discriminant of a quadratic function helps determine the number of x-intercepts:
D = b² - 4ac.
Depending on the value of D:
- If D > 0, there are two distinct x-intercepts.
- If D = 0, there is one x-intercept (the vertex touches the x-axis).
- If D < 0, there are no x-intercepts.
Example: Using the Discriminant
For the function f(x) = 2x² - 4x + 1:
D = (-4)² - 4(2)(1) = 16 - 8 = 8 (D > 0, two x-intercepts).
Solving Quadratic Inequalities
To solve a quadratic inequality, you can sketch the corresponding parabola and determine the intervals where the function is above or below the x-axis:
For example, to solve:
2x² - 4x + 1 < 0.
1. Find the x-intercepts (as done earlier).
2. Sketch the parabola.
3. Identify the intervals where the parabola is below the x-axis.
Common Mistakes
Watch out: Be careful when calculating the vertex. Mistakes in arithmetic can lead to incorrect results.
Watch out: When finding x-intercepts, ensure you apply the quadratic formula correctly, especially when dealing with negative numbers under the square root.
Summary
- A parabola is the graph of a quadratic function.
- The vertex is the highest or lowest point on the graph.
- The axis of symmetry is a vertical line through the vertex.
- Intercepts can be found by substituting values into the quadratic equation.
- The discriminant determines the number of x-intercepts.
Check your understanding
- What is the vertex of the parabola defined by f(x) = -3x² + 6x - 2?
- How does the value of a affect the shape of the parabola?
- What does the discriminant tell you about the roots of a quadratic equation?
- How would you sketch the parabola defined by f(x) = x² - 4?